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E = mc2

Scientific discovery and discussion
panamagold
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E = mc2

#16331

Postby panamagold » December 18th, 2016, 9:50 pm

E = energy (measured in joules, J)
m = mass (measured in kilograms, kg)
c = the speed of light (measured in metres per second, ms ), but this needs to be "squared".

jfgw
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Re: E = mc2

#16436

Postby jfgw » December 19th, 2016, 10:11 am

panamagold wrote:E = energy (measured in joules, J)
m = mass (measured in kilograms, kg)
c = the speed of light (measured in metres per second, ms ), but this needs to be "squared".


So why do I feel I have less energy since I have put on some extra mass?

redsturgeon
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Re: E = mc2

#16443

Postby redsturgeon » December 19th, 2016, 10:25 am

jfgw wrote:
panamagold wrote:E = energy (measured in joules, J)
m = mass (measured in kilograms, kg)
c = the speed of light (measured in metres per second, ms ), but this needs to be "squared".


So why do I feel I have less energy since I have put on some extra mass?


I think it is all relative.

John

AleisterCrowley
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Re: E = mc2

#16458

Postby AleisterCrowley » December 19th, 2016, 10:48 am

panamagold wrote:
c = the speed of light (measured in metres per second, ms ), but this needs to be "squared".

That bit has always 'bothered' me
What is a velocity squared?
It's definitely not a velocity.
10km/s = 6 miles/s approx
100km/s is not 36 miles/s

psychodom
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Re: E = mc2

#16498

Postby psychodom » December 19th, 2016, 12:14 pm

in the equation E = mc^2
it is equating the dimensions of Energy (Joules) to mass (kg) x speed (m / s) x speed (m / s)

so the units of 'c^2' are m^2 / s^2 (not just m/s)

so, in your example 100km^2 / s^2 is analogous to 36 miles^2 / s^2

-Dom

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Re: E = mc2

#16501

Postby AleisterCrowley » December 19th, 2016, 12:20 pm

OK so what is a second squared :?

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Re: E = mc2

#16505

Postby Percol351 » December 19th, 2016, 12:30 pm

It's always bothered me why it isn't E = (mc2)/2 like the equation for kinetic energy E= (mv2)/2

When I asked my physics teacher as a child I was fobbed off with because c is so large it doesn't matter about the 1/2.

Regards,

Percol

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Re: E = mc2

#16509

Postby psychodom » December 19th, 2016, 12:32 pm


psychodom
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Re: E = mc2

#16519

Postby psychodom » December 19th, 2016, 12:56 pm

Percol351 wrote:It's always bothered me why it isn't E = (mc2)/2 like the equation for kinetic energy E= (mv2)/2

When I asked my physics teacher as a child I was fobbed off with because c is so large it doesn't matter about the 1/2.

Regards,

Percol


E=mc^2 and the Newtonian Kinetic Energy equation are showing two different things.

The Newtonian equation for Kinetic Energy is E(k) = (m/v^2) / 2
The Relativistic equation for Kinetic Energy is E(k) = E(total energy) - E(rest energy)
E(k) = mc^2 / sqrt(1 - (v^2 / c^2) ) - mc^2

At low speeds (ie v << c) we can approximate this using the first two terms of a Taylor expansion for a reciprocal square root

E(k) ~ mc^2 (1 + v^2 / 2c^2) - mc^2 ~ (mv^2)/2
which is the Newtonian equation, i.e. at low speeds, relative to the speed of light, the Newtonian equation is a good approximation of the Relativistic equation.

-Dom

panamagold
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Re: E = mc2

#16523

Postby panamagold » December 19th, 2016, 1:09 pm

psychodom wrote:
E=mc^2 and the Newtonian Kinetic Energy equation are showing two different things.

The Newtonian equation for Kinetic Energy is E(k) = (m/v^2) / 2
The Relativistic equation for Kinetic Energy is E(k) = E(total energy) - E(rest energy)
E(k) = mc^2 / sqrt(1 - (v^2 / c^2) ) - mc^2

At low speeds (ie v << c) we can approximate this using the first two terms of a Taylor expansion for a reciprocal square root

E(k) ~ mc^2 (1 + v^2 / 2c^2) - mc^2 ~ (mv^2)/2
which is the Newtonian equation, i.e. at low speeds, relative to the speed of light, the Newtonian equation is a good approximation of the Relativistic equation.

-Dom


Wow....I am not worthy! :mrgreen:


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