This puzzle is to find all numbers between 1000 and 2300 each of which is
. the product of three squares (>1) and
. the sum of whose digits is also a square.
Happy new year to all readers.
Cinelli
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Squares
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- Lemon Quarter
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Re: Squares
There are of course two ways to solve the puzzle.
The easiest is to note that the product of squares is also a square and do an exhaustive search on the 16 squares between 1000 and 2300. Of these only 1521, 1681 and 2025 have digits that sum to a square and only 2025 has enough prime factors to be the product of three non-trivial squares.
The harder way, because it requires much more background, can be represented by the excel formula "=year(today())"
Happy New Year.
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- Lemon Slice
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Re: Squares
Well solved 9873210. That didn't take long.
Yes, the year 2025 is a perfect square and few will have seen one before. And it is unlikely that anyone here will live to see another. The fact that we are living in a square year even got a mention on the Today programme this morning.
Cinelli
Yes, the year 2025 is a perfect square and few will have seen one before. And it is unlikely that anyone here will live to see another. The fact that we are living in a square year even got a mention on the Today programme this morning.
Cinelli
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- The full Lemon
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Re: Squares
cinelli wrote:Yes, the year 2025 is a perfect square and few will have seen one before.
On the contrary, users of non-Roman calendars may well have done. For example, if my sources are correct our Jewish friends saw one just nine years ago.
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